gpg -u problem

[Peter Pentchev]

On Mon, Jul 20, 2009 at 10:09:03AM +0200, Nix wrote:
> Hello,
> 
> I have a problem with gpg (GnuPG) 1.4.9
> 
> I got three keys. I receive a crypted file and when i want to decrypt gpg
> don't want to use another key than the default.
> 
> i use this commande
> 
> gpg -u 5E95FE19 -d 00poap/gpg
> 
> Can you help me plz.

That should be "gpg -k 5E95FE19 -d 00poap/gpg", not "-u".
Either use -u 'Real Name' or -k keyid; in this case, 5E95FE19
is the key ID, not the user ID attached to this key.

G'luck,
Peter

-- 
Peter Pentchev	roam at ringlet.net    roam at space.bg    roam at FreeBSD.org
PGP key:	http://people.FreeBSD.org/~roam/roam.key.asc
Key fingerprint	FDBA FD79 C26F 3C51 C95E  DF9E ED18 B68D 1619 4553
What would this sentence be like if it weren't self-referential?
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