When using svn version gnupg, why isnt svn version shown with gpg --version

[Kevin Hilton]

Whats wrong with my version  -- I'm getting 1.48

$ gpg --version
gpg (GnuPG) 1.4.8-svn4702
Copyright (C) 2007 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.

Home: ~/.gnupg
Supported algorithms:
Pubkey: RSA, RSA-E, RSA-S, ELG-E, DSA
Cipher: IDEA, 3DES, CAST5, BLOWFISH, AES, AES192, AES256, TWOFISH, CAMELLIA128,

        CAMELLIA256
Hash: MD5, SHA1, RIPEMD160, SHA256, SHA384, SHA512, SHA224
Compression: Uncompressed, ZIP, ZLIB, BZIP2

My configure.ac (at least the top part looks like this:)
# Remember to change the version number immediately *after* a release.
# Set my_issvn to "yes" for non-released code.  Remember to run an
# "svn up" and "autogen.sh --force" right before creating a distribution.
m4_define([my_version], [1.4.8])
m4_define([my_issvn], [yes])

m4_define([svn_revision], m4_esyscmd([echo -n $((svn info 2>/dev/null \
          || echo 'Revision: 0')|sed -n '/^Revision:/ s/[^0-9]//gp'|head -1)]))

I'm guessing it should read like this:
m4_define([my_version], [1.4.9])

Since Im using the svn sources I would have thought this file would
have automatically at least been updated to 1.49 -- or am I missing
something.