getting signed text in plain

[Mario Lenz]

Hi @all!
        
I'm trying to get the "plaintext" out of a signature, but without any
success :-/

Here's a little bit of code to show you what I mean (I used a keyring
without a password for testing so I don't need to
gpgme_set_passphrase_cb):

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <gpgme.h>

int
main (int argc, char *argv[])
{
  gpgme_ctx_t ctx;
  gpgme_error_t err;
  gpgme_data_t plain, signed_text;
  char *agent_info, buffer[100];
  ssize_t size;

  gpgme_check_version (NULL);
  err = gpgme_engine_check_version (GPGME_PROTOCOL_OpenPGP);
  if (err)
    exit (1);

  err = gpgme_new (&ctx);
  if (err)
    exit (2);

  err = gpgme_data_new_from_mem (&plain, "Hallo Leute\n", 13, 0);
  if (err)
    exit (3);
  err = gpgme_data_new (&signed_text);
  if (err)
    exit (4);

  err = gpgme_op_sign (ctx, plain, signed_text, GPGME_SIG_MODE_NORMAL);
  if (err)
    exit (5);

  gpgme_data_release (plain);
  err = gpgme_data_new (&plain);
  if (err)
    exit (6);

  gpgme_data_seek (signed_text, 0, SEEK_SET);

  err = gpgme_op_verify (ctx, signed_text, NULL, plain);
  if (err)
    exit (7);

  gpgme_data_seek (plain, 0, SEEK_SET);
  size = gpgme_data_read (plain, buffer, 100);
  if (size > 0)
    printf ("%s\n", buffer);
  else
    printf ("failed with size %d\n", size);

  gpgme_data_release (plain);
  gpgme_data_release (signed_text);
  gpgme_release (ctx);
  return 0;
}

Although verification doesn't fail, I'm unable to get the signed text
out of plain. I've been trying this for some time now and wasn't able to
make it work. Could you please help me?

greez

   Mario
        
PS
I'm working on Debian Etch, but I linked the program above also against
the latest gpgme version (1.1.4) and the problem stays.

--
Rule One: Do not act incautiously when confronting little bald wrinkly
smiling men.