Newbie question: GnuPG and PGP

[Werner Koch]

On Sat, 6 Jan 2001, Jesus M. Salvo Jr. wrote:

> -----------------------------
> pub  1024D/51415191 2001-01-06 Jesus M. Salvo Jr. <jmsalvo@ihug.com.au>
> sig        51415191 2001-01-06  Jesus M. Salvo Jr. <jmsalvo@ihug.com.au>
> sub  1024g/8613FF52 2001-01-06 [expires: 2001-02-05]
> sig        51415191 2001-01-06  Jesus M. Salvo Jr. <jmsalvo@ihug.com.au>
> 
> 
> Can anyone tell me what that ( sub 1024g/8613FF52 means and why is it
> not the same as below? I did not create a key pair in GnuPG. All I did


> Type bits      keyID      Date       User ID
> DSS  1024      0x51415191 2001/01/06 expires 2001/02/05
>  DH  1024      0x51415191 2001/01/06 expires 2001/02/05

PGP is wrong.  Every key including subkeys have a unique KeyID and
by default GnuPG _and_ PGP 5,6,7 do create a primary and one
secindary key - the first one is used for signing, the second one for
encrypting (PGP calls ElGamal keys (the "g" in GnuPG's listing) DH
(Diffie Hellman))  I don't know why PGP lists the primary keys ID
with the DH subkey.

  Werner


-- 
Werner Koch                                              <wk@gnupg.org>
GNU Privacy Guard                                (http://www.gnupg.org)
Free Software Foundation Europe              (http://www.fsfeurope.org)
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