Decryption problem

[Johan Wevers]

Robert Fendt wrote:

> You should also get the file idea.c. Old PGP Algorithms were MD5, RSA, IDEA.
> Compiling should be like rsa.c. When generating messages, consider to use the
> switch --rfc1991 in order to generate messages that can be read by PGP 2.x.

I never got that to work. My ~/.gnupg/options file contains:

force-v3-sigs
load-extension rsa
load-extension idea
load-extension skipjack
compress-algo 1
cipher-algo IDEA
digest-algo MD5
s2k-cipher-algo IDEA
s2k-digest-algo MD5
rfc1991

When I encrypt a file with:

gpg -ca --rfc1991 filename

and then try to decrypt it with pgp 2.6.3ia, I get:

File is conventionally encrypted.
You need a pass phrase to decrypt this file.
Enter pass phrase: Just a moment...
Error:  Bad pass phrase.

Each time. I used a very simple pass phrase (just the word "test"), so I
doubt any code page subtleties are the problem.

The same problem when I use a public RSA key. When I try putting all options
on the command line I get:

vulcan:~/tmp> gpg --rfc1991 --s2k-digest-algo MD5 --digest-algo MD5
--cipher-algo IDEA --s2k-cipher-algo IDEA -u johanw filename
gpg: no valid OpenPGP data found.
gpg: processing message failed: eof

I want to use gpg to be able to communicate with PGP 2, 5 and 6 users without
giving up my pgp 2.x keys. Is this possible at all, or should I hack  gpg
for it?

-- 
ir. J.C.A. Wevers         //  Physics and science fiction site:
johanw@vulcan.xs4all.nl   //  http://www.xs4all.nl/~johanw/index.html
Finger johanw@xs4all.nl for my PGP public key.  PGP-KeyID: 0xD42F80B1